EIP4844: Handle barycentric evaluations at roots of unity

This commit is contained in:
George Kadianakis 2023-01-16 15:57:35 +02:00
parent 496e1d86c9
commit 296ba921c9
3 changed files with 71 additions and 3 deletions

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@ -302,11 +302,13 @@ def evaluate_polynomial_in_evaluation_form(polynomial: Polynomial,
assert width == FIELD_ELEMENTS_PER_BLOB
inverse_width = bls_modular_inverse(BLSFieldElement(width))
# Make sure we won't divide by zero during division
assert z not in ROOTS_OF_UNITY
roots_of_unity_brp = bit_reversal_permutation(ROOTS_OF_UNITY)
# If we are asked to evaluate within the domain, we already know the answer
if z in roots_of_unity_brp:
eval_index = roots_of_unity_brp.index(z)
return BLSFieldElement(polynomial[eval_index])
result = 0
for i in range(width):
a = BLSFieldElement(int(polynomial[i]) * int(roots_of_unity_brp[i]) % BLS_MODULUS)

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@ -4,6 +4,8 @@ from eth2spec.test.context import (
)
from eth2spec.test.helpers.sharding import (
get_sample_blob,
get_poly_in_both_forms,
eval_poly_in_coeff_form,
)
@ -18,3 +20,35 @@ def test_verify_kzg_proof(spec, state):
y = spec.evaluate_polynomial_in_evaluation_form(polynomial, x)
assert spec.verify_kzg_proof_impl(commitment, x, y, proof)
@with_eip4844_and_later
@spec_state_test
def test_barycentric_within_domain(spec, state):
"""
Test barycentric formula correctness by using it to evaluate a polynomial at all the points of its domain
(the roots of unity).
Then make sure that we would get the same result if we evaluated it from coefficient form without using the
barycentric formula
"""
poly_coeff, poly_eval = get_poly_in_both_forms(spec)
roots_of_unity_brp = spec.bit_reversal_permutation(spec.ROOTS_OF_UNITY)
assert len(poly_coeff) == len(poly_eval) == len(roots_of_unity_brp)
n = len(poly_coeff)
# Iterate over the entire domain
for i in range(n):
# Grab a root of unity and use it as the evaluation point
z = int(roots_of_unity_brp[i])
# Get p(z) by evaluating poly in coefficient form
p_z_coeff = eval_poly_in_coeff_form(spec, poly_coeff, z)
# Get p(z) by evaluating poly in evaluation form
p_z_eval = spec.evaluate_polynomial_in_evaluation_form(poly_eval, z)
# The two evaluations should be agree and p(z) should also be the i-th "coefficient" of the polynomial in
# evaluation form
assert p_z_coeff == p_z_eval == poly_eval[i]

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@ -66,6 +66,38 @@ def get_sample_blob(spec, rng=None):
return spec.Blob(b)
def eval_poly_in_coeff_form(spec, coeffs, x):
"""
Evaluate a polynomial in coefficient form at 'x' using Horner's rule
"""
total = 0
for a in reversed(coeffs):
total = (total * x + a) % spec.BLS_MODULUS
return total % spec.BLS_MODULUS
def get_poly_in_both_forms(spec, rng=None):
"""
Generate and return a random polynomial in both coefficient form and evaluation form
"""
if rng is None:
rng = random.Random(5566)
roots_of_unity_brp = spec.bit_reversal_permutation(spec.ROOTS_OF_UNITY)
coeffs = [
rng.randint(0, spec.BLS_MODULUS - 1)
for _ in range(spec.FIELD_ELEMENTS_PER_BLOB)
]
evals = [
eval_poly_in_coeff_form(spec, coeffs, int(z))
for z in roots_of_unity_brp
]
return coeffs, evals
def get_sample_opaque_tx(spec, blob_count=1, rng=None):
blobs = []
blob_kzg_commitments = []