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docs(test): handle IHAVE / IWANT tests (#1202)
Add documentation as requested.
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@ -677,55 +677,76 @@ suite "GossipSub internal":
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gossipSub.mesh[topic] = initHashSet[PubSubPeer]()
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gossipSub.subscribe(topic, handler2)
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# Instantiates 30 peers and connects all of them to the previously defined `gossipSub`
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for i in 0 ..< 30:
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# Define a new connection
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let conn = TestBufferStream.new(noop)
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conns &= conn
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let peerId = randomPeerId()
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conn.peerId = peerId
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let peer = gossipSub.getPubSubPeer(peerId)
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peer.handler = handler
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# Add the connection to `gossipSub`, to their `gossipSub.gossipsub` and `gossipSub.mesh` tables
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gossipSub.grafted(peer, topic)
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gossipSub.mesh[topic].incl(peer)
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# Peers with no budget should not request messages
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block:
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# should ignore no budget peer
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let conn = TestBufferStream.new(noop)
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conns &= conn
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let peerId = randomPeerId()
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conn.peerId = peerId
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let peer = gossipSub.getPubSubPeer(peerId)
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let id = @[0'u8, 1, 2, 3]
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let msg = ControlIHave(topicID: topic, messageIDs: @[id, id, id])
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peer.iHaveBudget = 0
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let iwants = gossipSub.handleIHave(peer, @[msg])
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check:
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iwants.messageIDs.len == 0
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block:
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# given duplicate ihave should generate only one iwant
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let conn = TestBufferStream.new(noop)
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conns &= conn
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let peerId = randomPeerId()
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conn.peerId = peerId
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let peer = gossipSub.getPubSubPeer(peerId)
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let id = @[0'u8, 1, 2, 3]
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let msg = ControlIHave(topicID: topic, messageIDs: @[id, id, id])
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let iwants = gossipSub.handleIHave(peer, @[msg])
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check:
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iwants.messageIDs.len == 1
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block:
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# given duplicate iwant should generate only one message
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# Define a new connection
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let conn = TestBufferStream.new(noop)
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conns &= conn
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let peerId = randomPeerId()
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conn.peerId = peerId
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let peer = gossipSub.getPubSubPeer(peerId)
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# Add message to `gossipSub`'s message cache
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let id = @[0'u8, 1, 2, 3]
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gossipSub.mcache.put(id, Message())
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peer.sentIHaves[^1].incl(id)
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# Build an IHAVE message that contains the same message ID three times
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let msg = ControlIHave(topicID: topic, messageIDs: @[id, id, id])
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# Given the peer has no budget to request messages
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peer.iHaveBudget = 0
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# When a peer makes an IHAVE request for the a message that `gossipSub` has
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let iwants = gossipSub.handleIHave(peer, @[msg])
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# Then `gossipSub` should not generate an IWant message for the message,
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check:
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iwants.messageIDs.len == 0
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# Peers with budget should request messages. If ids are repeated, only one request should be generated
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block:
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# Define a new connection
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let conn = TestBufferStream.new(noop)
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conns &= conn
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let peerId = randomPeerId()
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conn.peerId = peerId
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let peer = gossipSub.getPubSubPeer(peerId)
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let id = @[0'u8, 1, 2, 3]
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# Build an IHAVE message that contains the same message ID three times
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let msg = ControlIHave(topicID: topic, messageIDs: @[id, id, id])
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# Given the budget is not 0 (because it's not been overridden)
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# When a peer makes an IHAVE request for the a message that `gossipSub` does not have
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let iwants = gossipSub.handleIHave(peer, @[msg])
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# Then `gossipSub` should generate an IWant message for the message
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check:
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iwants.messageIDs.len == 1
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# Peers with budget should request messages. If ids are repeated, only one request should be generated
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block:
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# Define a new connection
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let conn = TestBufferStream.new(noop)
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conns &= conn
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let peerId = randomPeerId()
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conn.peerId = peerId
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let peer = gossipSub.getPubSubPeer(peerId)
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# Add message to `gossipSub`'s message cache
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let id = @[0'u8, 1, 2, 3]
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gossipSub.mcache.put(id, Message())
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peer.sentIHaves[^1].incl(id)
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# Build an IWANT message that contains the same message ID three times
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let msg = ControlIWant(messageIDs: @[id, id, id])
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# When a peer makes an IWANT request for the a message that `gossipSub` has
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let genmsg = gossipSub.handleIWant(peer, @[msg])
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# Then `gossipSub` should return the message
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check:
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genmsg.len == 1
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