react-native/Libraries/Utilities/groupByEveryN.js
Alex Kotliarskyi fab5ec617d Updates from Tue Mar 10
- [ReactNative] Make tests run on TravisCI | Alex Kotliarskyi
- [Relay] Update Relay + ES6 class containers | Christoph Pojer
- [React Native] Add RCTAdSupport.xcodeproj | Alexsander Akers
- [ReactNative][Android] Fix after a new React version was downstreamed | Philipp von Weitershausen
- [React Native] Add preliminary animation API | Alex Akers
- [ReactKit] Create test for OSS ReactKit | Alex Kotliarskyi
- [React Native][Device ID][wip] implement most basic js access | Alex Akers
- [ReactNative] OSS Picker | Spencer Ahrens
- [ReactNative] Fix typo in RCTUIManager | Tadeu Zagallo
- [ReactNative] Fix GeoLocation files letter case | Tadeu Zagallo
- Unified the method signature for addUIBlock: to further simplify porting ViewManagers | Nick Lockwood
- [ReactNative] Oss GeoMap | Tadeu Zagallo
- [ReactNative] OSS CameraRoll | Tadeu Zagallo
- [ReactNative] allowLossyConversion on NSString->NSData conversion | Andrew Rasmussen
- [React Native][RFC] Print __DEV__ value on app start | Alex Kotliarskyi
2015-03-10 19:54:10 -07:00

47 lines
993 B
JavaScript

/**
* Copyright 2004-present Facebook. All Rights Reserved.
*
* @providesModule groupByEveryN
*/
/**
* Useful method to split an array into groups of the same number of elements.
* You can use it to generate grids, rows, pages...
*
* If the input length is not a multiple of the count, it'll fill the last
* array with null so you can display a placeholder.
*
* Example:
* groupByEveryN([1, 2, 3, 4, 5], 3)
* => [[1, 2, 3], [4, 5, null]]
*
* groupByEveryN([1, 2, 3], 2).map(elems => {
* return <Row>{elems.map(elem => <Elem>{elem}</Elem>)}</Row>;
* })
*/
'use strict';
function groupByEveryN(array, n) {
var result = [];
var temp = [];
for (var i = 0; i < array.length; ++i) {
if (i > 0 && i % n === 0) {
result.push(temp);
temp = [];
}
temp.push(array[i]);
}
if (temp.length > 0) {
while (temp.length !== n) {
temp.push(null);
}
result.push(temp);
}
return result;
}
module.exports = groupByEveryN;