p2p: move peerList back into baseProtocol

It had been moved to Peer, probably for debugging.

p2p/peer.go

@@ -460,25 +460,3 @@ func (r *eofSignal) Read(buf []byte) (int, error) {
 	}
 	return n, err
 }
-
-func (peer *Peer) PeerList() []interface{} {
-	peers := peer.otherPeers()
-	ds := make([]interface{}, 0, len(peers))
-	for _, p := range peers {
-		p.infolock.Lock()
-		addr := p.listenAddr
-		p.infolock.Unlock()
-		// filter out this peer and peers that are not listening or
-		// have not completed the handshake.
-		// TODO: track previously sent peers and exclude them as well.
-		if p == peer || addr == nil {
-			continue
-		}
-		ds = append(ds, addr)
-	}
-	ourAddr := peer.ourListenAddr
-	if ourAddr != nil && !ourAddr.IP.IsLoopback() && !ourAddr.IP.IsUnspecified() {
-		ds = append(ds, ourAddr)
-	}
-	return ds
-}

p2p/protocol.go

@@ -169,7 +169,7 @@ func (bp *baseProtocol) handle(rw MsgReadWriter) error {
 	case pongMsg:
 
 	case getPeersMsg:
-		peers := bp.peer.PeerList()
+		peers := bp.peerList()
 		// this is dangerous. the spec says that we should _delay_
 		// sending the response if no new information is available.
 		// this means that would need to send a response later when
@@ -264,3 +264,25 @@ func (bp *baseProtocol) handshakeMsg() Msg {
 		bp.peer.ourID.Pubkey()[1:],
 	)
 }
+
+func (bp *baseProtocol) peerList() []interface{} {
+	peers := bp.peer.otherPeers()
+	ds := make([]interface{}, 0, len(peers))
+	for _, p := range peers {
+		p.infolock.Lock()
+		addr := p.listenAddr
+		p.infolock.Unlock()
+		// filter out this peer and peers that are not listening or
+		// have not completed the handshake.
+		// TODO: track previously sent peers and exclude them as well.
+		if p == bp.peer || addr == nil {
+			continue
+		}
+		ds = append(ds, addr)
+	}
+	ourAddr := bp.peer.ourListenAddr
+	if ourAddr != nil && !ourAddr.IP.IsLoopback() && !ourAddr.IP.IsUnspecified() {
+		ds = append(ds, ourAddr)
+	}
+	return ds
+}