Add divmod i.e. division + modulo done!

This commit is contained in:
mratsim 2018-02-16 22:17:13 +01:00
parent a8f50c4dbe
commit 1c5da77a29
3 changed files with 62 additions and 10 deletions

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@ -9,27 +9,34 @@ macro getSubType*(T: typedesc): untyped =
## MpUint[uint32] --> uint32 ## MpUint[uint32] --> uint32
getTypeInst(T)[1][1] getTypeInst(T)[1][1]
proc bit_length*[T: SomeUnsignedInt](n: T): int {.noSideEffect.}=
proc bit_length*[T: BaseUint](n: T): int {.noSideEffect.}=
## Calculates how many bits are necessary to represent the number ## Calculates how many bits are necessary to represent the number
result = 1 result = 1
var y: T = n shr 1 var y: T = n shr 1
while y > 0.T: while y != 0.T:
y = y shr 1 y = y shr 1
inc(result) inc(result)
proc bit_length*[T: Natural](n: T): int {.noSideEffect.}= proc bit_length*[T: Natural](n: T): int {.noSideEffect.}=
## Calculates how many bits are necessary to represent the number ## Calculates how many bits are necessary to represent the number
# #
# For some reason using "BaseUint or Natural" directly makes Nim compiler # For some reason using "SomeUnsignedInt or Natural" directly makes Nim compiler
# throw a type mismatch # throw a type mismatch
result = 1 result = 1
var y: T = n shr 1 var y: T = n shr 1
while y > 0.T: while y != 0.T:
y = y shr 1 y = y shr 1
inc(result) inc(result)
proc bit_length*[T: MpUint](n: T): int {.noSideEffect.}=
## Calculates how many bits are necessary to represent the number
const zero = T()
result = 1
var y: T = n shr 1
while y != zero:
y = y shr 1 # TODO: shr is slow!
inc(result)
proc asUint*[T: MpUInt](n: T): auto {.noSideEffect, inline.}= proc asUint*[T: MpUInt](n: T): auto {.noSideEffect, inline.}=
## Casts a multiprecision integer to an uint of the same size ## Casts a multiprecision integer to an uint of the same size

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@ -106,3 +106,48 @@ proc naiveMul[T: BaseUint](x, y: T): MpUint[T] {.noSideEffect, noInit, inline.}=
# Case: at least uint128 * uint128 --> uint256 # Case: at least uint128 * uint128 --> uint256
naiveMulImpl(x, y) naiveMulImpl(x, y)
proc divmod*[T: BaseUint](x, y: T): tuple[quot, rem: T] {.noSideEffect.}=
## Division for multi-precision unsigned uint
## Returns quotient + reminder in a (quot, rem) tuple
#
# Implementation through binary shift division
const zero = T()
when x.lo is MpUInt:
const one = T(lo: getSubType(T)(1))
const mpOne = one
else:
const one: getSubType(T) = 1
const mpOne = T(lo: getSubType(T)(1))
if y == zero:
raise newException(DivByZeroError, "You attempted to divide by zero")
elif y == mpOne:
result.quot = x
return
var
shift = x.bit_length - y.bit_length
d = y shl shift
result.rem = x
while shift >= 0:
result.quot = result.quot shl 1
if result.rem >= d:
result.rem -= d
result.quot.lo = result.quot.lo or one
d = d shr 1
dec(shift)
# Performance note:
# The performance of this implementation is extremely dependant on shl and shr.
#
# Probably the most efficient algorithm that can benefit from MpUInt data structure is
# the recursive fast division by Burnikel and Ziegler (http://www.mpi-sb.mpg.de/~ziegler/TechRep.ps.gz):
# - Python implementation: https://bugs.python.org/file11060/fast_div.py and discussion https://bugs.python.org/issue3451
# - C++ implementation: https://github.com/linbox-team/givaro/blob/master/src/kernel/recint/rudiv.h
# - The Handbook of Elliptic and Hyperelliptic Cryptography Algorithm 10.35 on page 188 has a more explicit version of the div2NxN algorithm. This algorithm is directly recursive and avoids the mutual recursion of the original paper's calls between div2NxN and div3Nx2N.
# - Comparison of fast division algorithms fro large integers: http://bioinfo.ict.ac.cn/~dbu/AlgorithmCourses/Lectures/Hasselstrom2003.pdf

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@ -34,7 +34,7 @@ proc `shl`*[T: MpUint](x: T, y: SomeInteger): T {.noInit, noSideEffect.}=
if y == 0: if y == 0:
return x return x
let # cannot be const, compile-time sizeof only works for simple types let
size = T.sizeof * 8 size = T.sizeof * 8
halfSize = size div 2 halfSize = size div 2
@ -53,7 +53,7 @@ proc `shr`*[T: MpUint](x: T, y: SomeInteger): T {.noInit, noSideEffect.}=
if y == 0: if y == 0:
return x return x
let # cannot be const, compile-time sizeof only works for simple types let
size = T.sizeof * 8 size = T.sizeof * 8
halfSize = size div 2 halfSize = size div 2
@ -97,7 +97,7 @@ proc `shr`*[T: MpUint](x: T, y: SomeInteger): T {.noInit, noSideEffect.}=
# result.hi = (x.lo shl S) and not M2 # result.hi = (x.lo shl S) and not M2
# result.lo = (x.lo shl S) and M2 # result.lo = (x.lo shl S) and M2
# result.hi = result.hi or (( # result.hi = result.hi or ((
# x.hi shl S or (x.lo shr (size - S) and M1) # x.hi shl S or (x.lo shr (halfSize - S) and M1)
# ) and M2) # ) and M2)
# proc `shr`*[T: MpUint](x: T, y: SomeInteger): T {.noInit, noSideEffect.}= # proc `shr`*[T: MpUint](x: T, y: SomeInteger): T {.noInit, noSideEffect.}=
@ -119,5 +119,5 @@ proc `shr`*[T: MpUint](x: T, y: SomeInteger): T {.noInit, noSideEffect.}=
# result.lo = (x.hi shr S) and not M2 # result.lo = (x.hi shr S) and not M2
# result.hi = (x.hi shr S) and M2 # result.hi = (x.hi shr S) and M2
# result.lo = result.lo or (( # result.lo = result.lo or ((
# x.lo shr S or (x.lo shl (size - S) and M1) # x.lo shr S or (x.hi shl (halfSize - S) and M1)
# ) and M2) # ) and M2)