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Add task_spec_name to add_file API call

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This commit is contained in:
mike cullerton 2021-08-26 10:37:05 -04:00
parent 3d7dadc319
commit 4c41011299
2 changed files with 11 additions and 1 deletions
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6
crc/api.yml
View File

@ -699,6 +699,12 @@ paths:
description: The unique id of a workflow instance
schema:
type: integer
- name: task_spec_name
in: query
required: false
description: The name of the task spec
schema:
type: string
- name: form_field_key
in: query
required: false

6
crc/api/file.py
View File

@ -41,13 +41,17 @@ def get_reference_files():
return FileSchema(many=True).dump(files)
def add_file(workflow_spec_id=None, workflow_id=None, form_field_key=None):
def add_file(workflow_spec_id=None, workflow_id=None, task_spec_name=None, form_field_key=None):
file = connexion.request.files['file']
if workflow_id:
if form_field_key is None:
raise ApiError('invalid_workflow_file',
'When adding a workflow related file, you must specify a form_field_key')
if task_spec_name is None:
raise ApiError('invalid_workflow_file',
'When adding a workflow related file, you must specify a task_spec_name')
file_model = FileService.add_workflow_file(workflow_id=workflow_id, irb_doc_code=form_field_key,
task_spec_name=task_spec_name,
name=file.filename, content_type=file.content_type,
binary_data=file.stream.read())
elif workflow_spec_id: