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Support for .?[] operator on openArrays (#52)
* Support for .?[] operator on openArrays * Operator .?[] evaluates openArray expression only once * Fix for Nim 1.2.x --------- Co-authored-by: Mark Spanbroek <mark@spanbroek.net>
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@ -1,16 +1,24 @@
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import std/macros
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import std/options
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macro `.?`*(expression: seq | string, brackets: untyped{nkBracket}): untyped =
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# chain is of shape: (seq or string).?[index]
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let index = brackets[0]
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quote do:
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block:
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type T = typeof(`expression`[`index`])
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let evaluated = `expression`
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if `index` < evaluated.len:
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evaluated[`index`].some
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else:
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T.none
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proc safeGet[T](expression: seq[T] | openArray[T], index: int): Option[T] =
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if index >= expression.low and index <= expression.high:
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expression[index].some
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else:
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T.none
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proc safeGet(expression: string, index: int): Option[char] =
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if index >= expression.low and index <= expression.high:
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expression[index].some
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else:
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char.none
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macro `.?`*(expression: seq | string | openArray, brackets: untyped{nkBracket}): untyped =
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# chain is of shape: (seq or string or openArray).?[index]
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let index = brackets[0]
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quote do:
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block:
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safeGet(`expression`, `index`)
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macro `.?`*(expression: typed, brackets: untyped{nkBracket}): untyped =
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# chain is of shape: expression.?[index]
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@ -337,13 +337,28 @@ suite "optionals":
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test ".?[] can be used for indexing strings without raising IndexDefect":
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let str = "a"
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check str.?[0] == 'a'.some
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check str.?[0] == 'a'.some
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check str.?[1] == char.none
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check str.?[-1] == char.none
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test ".?[] can be used for indexing sequences without raising IndexDefect":
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let sequence = @[1]
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check sequence.?[0] == 1.some
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check sequence.?[1] == int.none
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check sequence.?[-1] == int.none
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test ".?[] can be used for indexing openArrays without raising IndexDefect":
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proc checkOpenArray(oa: openArray[int]): void =
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check oa.?[0] == 1.some
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check oa.?[1] == int.none
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check oa.?[-1] == int.none
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checkOpenArray(@[1])
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test ".?[] evaluates openArray expression only once":
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var count = 0
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discard (inc count; @[1].toOpenArray(0, 0)).?[0]
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check count == 1
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test ".?[] can be followed by calls, operators and indexing":
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let table = @{"a": @[41, 42]}.toTable
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