Got fix for #8 in go-libp2p-pubsub.

Enable full test.

tests/testdaemon.nim

@@ -48,16 +48,16 @@ proc provideBadCidTest(): Future[bool] {.async.} =
   finally:
     await api.close()
 
-proc getOnlyOneIPv4Address(addresses: seq[MultiAddress]): seq[MultiAddress] =
-  ## We doing this becuase of bug in `go-pubsub`
-  ## https://github.com/libp2p/go-libp2p-pubsub/issues/130
-  if len(addresses) > 0:
-    result = newSeqOfCap[MultiAddress](len(addresses))
-    let ip4 = multiCodec("ip4")
-    for item in addresses:
-      if item.protoCode() == ip4:
-        result.add(item)
-        break
+# proc getOnlyOneIPv4Address(addresses: seq[MultiAddress]): seq[MultiAddress] =
+#   ## We doing this becuase of bug in `go-pubsub`
+#   ## https://github.com/libp2p/go-libp2p-pubsub/issues/130
+#   if len(addresses) > 0:
+#     result = newSeqOfCap[MultiAddress](len(addresses))
+#     let ip4 = multiCodec("ip4")
+#     for item in addresses:
+#       if item.protoCode() == ip4:
+#         result.add(item)
+#         break
 
 proc pubsubTest(f: set[P2PDaemonFlags]): Future[bool] {.async.} =
   var pubsubData = "TEST MESSAGE"
@@ -95,10 +95,8 @@ proc pubsubTest(f: set[P2PDaemonFlags]): Future[bool] {.async.} =
     # Callback must return `false` to close subscription channel.
     result = false
 
-  # Not subscribed to any topics everything must be 0.
-  # We are making only one connection, because of bug
-  # https://github.com/libp2p/go-libp2p-pubsub/issues/130
-  await api1.connect(id2.peer, getOnlyOneIPv4Address(id2.addresses))
+  await api1.connect(id2.peer, id2.addresses)
+  await api2.connect(id1.peer, id1.addresses)
 
   var ticket1 = await api1.pubsubSubscribe("test-topic", pubsubHandler1)
   var ticket2 = await api2.pubsubSubscribe("test-topic", pubsubHandler2)