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Fix #2285 : Speed optimizations for sessionproxy
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@ -89,10 +89,7 @@ class SessionProxyTestCase(unittest.TestCase):
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d = self.sp.start()
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def do_get_torrents_status(torrent_ids):
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inital_keys = [
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'queue', 'state', 'name', 'total_wanted', 'progress', 'state',
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'download_payload_rate', 'upload_payload_rate', 'eta', 'owner'
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]
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inital_keys = ['key1']
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self.sp.get_torrents_status({'id': torrent_ids}, inital_keys)
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d.addCallback(do_get_torrents_status)
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return d
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@ -99,18 +99,36 @@ class SessionProxy(component.Component):
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"""
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sd = {}
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keys = set(keys)
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keys_len = -1 # The number of keys for the current cache (not the len of keys_diff_cached)
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keys_diff_cached = []
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for torrent_id in torrent_ids:
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try:
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if keys:
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sd[torrent_id] = dict([
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(x, y) for x, y in self.torrents[torrent_id][1].iteritems()
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if x in keys
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])
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sd[torrent_id] = self.torrents[torrent_id][1].copy()
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# Have to remove the keys that weren't requested
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if len(sd[torrent_id]) == keys_len:
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# If the number of keys are equal they are the same keys
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# so we use the cached diff of the keys we need to remove
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keys_to_remove = keys_diff_cached
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else:
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# Not the same keys so create a new diff
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keys_to_remove = set(sd[torrent_id].iterkeys()) - keys
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# Update the cached diff
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keys_diff_cached = keys_to_remove
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keys_len = len(sd[torrent_id])
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# Usually there are no keys to remove, so it's cheaper with
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# this if-test than a for-loop with no iterations.
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if keys_to_remove:
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for k in keys_to_remove:
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del sd[torrent_id][k]
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else:
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sd[torrent_id] = dict(self.torrents[torrent_id][1])
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except KeyError:
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continue
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return sd
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def get_torrent_status(self, torrent_id, keys):
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@ -184,7 +202,7 @@ class SessionProxy(component.Component):
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def on_status(result, torrent_ids, keys):
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# Update the internal torrent status dict with the update values
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t = time.time()
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for key, value in result.items():
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for key, value in result.iteritems():
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try:
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self.torrents[key][0] = t
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self.torrents[key][1].update(value)
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