# Constantine
# Copyright (c) 2018-2019 Status Research & Development GmbH
# Copyright (c) 2020-Present Mamy André-Ratsimbazafy
# Licensed and distributed under either of
# * MIT license (license terms in the root directory or at http://opensource.org/licenses/MIT).
# * Apache v2 license (license terms in the root directory or at http://www.apache.org/licenses/LICENSE-2.0).
# at your option. This file may not be copied, modified, or distributed except according to those terms.
# This script checks polynomial irreducibility
#
# Constructing Tower Extensions for the implementation of Pairing-Based Cryptography
# Naomi Benger and Michael Scott, 2009
# https://eprint.iacr.org/2009/556
# ############################################################
#
# Failed experiments of actually instantiating
# the tower of extension fields
#
# ############################################################
# ############################################################
# 1st try
# # Create the field of x ∈ [0, p-1]
# K.
= NumberField(x - 1)
#
# # Tower Fp² with Fp[u] / (u² + 1) <=> u = 𝑖
# L. = K.extension(x^2 + 1)
#
# TODO how to make the following work?
# # Tower Fp^6 with Fp²[v] / (v³ - (u + 1))
# M. = L.extension(x^3 - (im + 1))
# ############################################################
# 2nd try
# # Create the field of u ∈ [0, p-1]
# p = Integer('0x30644e72e131a029b85045b68181585d97816a916871ca8d3c208c16d87cfd47')
# Fp = GF(p)
# Elem. = Fp[]
# print("p mod 4 = ", p % 4)
#
# # Tower Fp² with Fp[u] / (u² + 1) <=> u = 𝑖
# Fp2. = Fp.extension(u^2 + 1)
# Elem2. = Fp2[]
#
# # Tower Fp^6 with Fp²[v] / (v³ - (u + 1))
# Fp6. = Fp.extension(v^3 - (im + 1))
# Elem6. = Fp6[]
# ############################################################
# 3rd try
# K. = NumberField([x^3 - I - 1, x^2 + 1, x - 1])
# ############################################################
# 4th try, just trying to verify Fp6
# print('Verifying non-residues')
# modulus = Integer('0x30644e72e131a029b85045b68181585d97816a916871ca8d3c208c16d87cfd47')
# Fp. = NumberField(x - 1)
# r1 = Fp(-1).residue_symbol(Fp.ideal(modulus),2)
# print('Fp² = Fp[sqrt(-1)]: ' + str(r1))
# Fp2. = Fp.extension(x^2 + 1)
# xi = Fp2(1+im)
# r2 = xi.residue_symbol(Fp2.ideal(modulus),3)
# # ValueError: The residue symbol to that power is not defined for the number field
# # ^ AFAIK that means that Fp2 doesn't contain the 3rd root of unity
# # so we are clear
# print('Fp6 = Fp²[cubicRoot(1+I)]: ' + str(r2))