Introduce alternate conversion to Montgomery Residue based on Montgomery Multiplication

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Mamy André-Ratsimbazafy 2020-02-15 19:22:40 +01:00
parent e2333dce3c
commit 4970572393
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6 changed files with 212 additions and 70 deletions

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@ -9,7 +9,9 @@
import
./io_bigints,
../config/curves,
../math/[bigints_checked, finite_fields]
../math/[bigints_checked, finite_fields],
# TODO: should be a const/proc in curves.nim
../math/precomputed
# ############################################################
#
@ -21,8 +23,8 @@ func fromUint*(dst: var Fq,
src: SomeUnsignedInt) =
## Parse a regular unsigned integer
## and store it into a BigInt of size `bits`
dst.mres.fromRawUint(cast[array[sizeof(src), byte]](src), cpuEndian)
dst.mres.unsafeMontyResidue(Fq.C.Mod.mres)
let raw = (type dst.mres).fromRawUint(cast[array[sizeof(src), byte]](src), cpuEndian)
dst.mres.unsafeMontyResidue(raw, Fq.C.Mod.mres, r2mod(Fq.C.Mod.mres), neginvModWord(Fq.C.Mod.mres))
func serializeRawUint*(dst: var openarray[byte],
src: Fq,

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@ -111,15 +111,22 @@ func reduce*[aBits, mBits](r: var BigInt[mBits], a: BigInt[aBits], M: BigInt[mBi
# pass a pointer+length to a fixed session of the BSS.
reduce(r.view, a.view, M.view)
func unsafeMontyResidue*[mBits](mres: var BigInt[mBits], N: BigInt[mBits]) =
func unsafeMontyResidue*[mBits](mres: var BigInt[mBits], a, N, r2modN: BigInt[mBits], negInvModWord: static BaseType) =
## Convert a BigInt from its natural representation
## to the Montgomery n-residue form
##
## `mres` is modified in-place
## `mres` is overwritten. It's bitlength must be properly set before calling this procedure.
##
## Caller must take care of properly switching between
## the natural and montgomery domain.
## Nesting Montgomery form is possible by applying this function twice.
# TODO: benchmark
when true:
# Montgomery multiplication based
montyResidue(mres.view, a.view, N.view, r2modN.view, Word(negInvModWord))
else:
# Modular left shift based
mres = a
montyResidue(mres.view, N.view)
func unsafeRedc*[mBits](mres: var BigInt[mBits], N: BigInt[mBits], negInvModWord: static BaseType) =

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@ -393,31 +393,61 @@ func reduce*(r: BigIntViewMut, a: BigIntViewAny, M: BigIntViewConst) =
#
# ############################################################
func montyResidue*(a: BigIntViewMut, N: BigIntViewConst) =
## Transform a bigint ``a`` from it's natural representation (mod N)
## to a the Montgomery n-residue representation
##
## with W = N.numLimbs()
## and R = (2^WordBitSize)^W
##
## Does "a * R (mod N)"
##
## `a`: The source BigInt in the natural representation. `a` in [0, N) range
## `N`: The field modulus. N must be odd.
##
## Important: `a` is overwritten
# Reference: https://eprint.iacr.org/2017/1057.pdf
checkValidModulus(N)
checkOddModulus(N)
checkMatchingBitlengths(a, N)
let nLen = N.numLimbs()
for i in countdown(nLen, 1):
a.shlAddMod(Zero, N)
template wordMul(a, b: Word): Word =
(a * b) and MaxWord
func montyMul*(
r: BigIntViewMut, a, b: distinct BigIntViewAny,
M: BigIntViewConst, negInvModWord: Word) =
## Compute r <- a*b (mod M) in the Montgomery domain
## `negInvModWord` = -1/M (mod Word). Our words are 2^31 or 2^63
##
## This resets r to zero before processing. Use {.noInit.}
## to avoid duplicating with Nim zero-init policy
## The result `r` buffer size MUST be at least the size of `M` buffer
##
##
## Assuming 63-bit wors, the magic constant should be:
##
## - µ ≡ -1/M[0] (mod 2^63) for a general multiplication
## This can be precomputed with `negInvModWord`
## - 1 for conversion from Montgomery to canonical representation
## The library implements a faster `redc` primitive for that use-case
## - R^2 (mod M) for conversion from canonical to Montgomery representation
##
# i.e. c'R <- a'R b'R * R^-1 (mod M) in the natural domain
# as in the Montgomery domain all numbers are scaled by R
checkValidModulus(M)
checkOddModulus(M)
checkMatchingBitlengths(a, M)
checkMatchingBitlengths(b, M)
let nLen = M.numLimbs()
r.setBitLength(bitSizeof(M))
setZero(r)
var r_hi = Zero # represents the high word that is used in intermediate computation before reduction mod M
for i in 0 ..< nLen:
let zi = (r[0] + wordMul(a[i], b[0])).wordMul(negInvModWord)
var carry = Zero
for j in 0 ..< nLen:
let z = DoubleWord(r[j]) + unsafeExtPrecMul(a[i], b[j]) +
unsafeExtPrecMul(zi, M[j]) + DoubleWord(carry)
carry = Word(z shr WordBitSize)
if j != 0:
r[j-1] = Word(z) and MaxWord
r_hi += carry
r[^1] = r_hi and MaxWord
r_hi = r_hi shr WordBitSize
# If the extra word is not zero or if r-M does not borrow (i.e. r > M)
# Then substract M
discard r.sub(M, r_hi.isNonZero() or not r.sub(M, CtFalse))
func redc*(a: BigIntViewMut, N: BigIntViewConst, negInvModWord: Word) =
## Transform a bigint ``a`` from it's Montgomery N-residue representation (mod N)
## to the regular natural representation (mod N)
@ -455,43 +485,54 @@ func redc*(a: BigIntViewMut, N: BigIntViewConst, negInvModWord: Word) =
a[^1] = Word(carry)
func montyMul*(
r: BigIntViewMut, a, b: distinct BigIntViewAny,
M: BigIntViewConst, negInvModWord: Word) =
## Compute r <- a*b (mod M) in the Montgomery domain
## `negInvModWord` = -1/M (mod Word). Our words are 2^31 or 2^63
# TODO: benchmark Montgomery Multiplication vs Shift-Left (after constant-time division)
func montyResidue*(
r: BigIntViewMut, a: BigIntViewAny,
N, r2modN: BigIntViewConst, negInvModWord: Word) =
## Transform a bigint ``a`` from it's natural representation (mod N)
## to a the Montgomery n-residue representation
##
## This resets r to zero before processing. Use {.noInit.}
## to avoid duplicating with Nim zero-init policy
# i.e. c'R <- a'R b'R * R^-1 (mod M) in the natural domain
# as in the Montgomery domain all numbers are scaled by R
## Montgomery-Multiplication - based
##
## with W = N.numLimbs()
## and R = (2^WordBitSize)^W
##
## Does "a * R (mod N)"
##
## `a`: The source BigInt in the natural representation. `a` in [0, N) range
## `N`: The field modulus. N must be odd.
## `r2modN`: 2^WordBitSize mod `N`. Can be precomputed with `r2mod` function
##
## Important: `r` is overwritten
## The result `r` buffer size MUST be at least the size of `M` buffer
# Reference: https://eprint.iacr.org/2017/1057.pdf
checkValidModulus(N)
checkOddModulus(N)
checkMatchingBitlengths(a, N)
checkValidModulus(M)
checkOddModulus(M)
checkMatchingBitlengths(r, M)
checkMatchingBitlengths(a, M)
checkMatchingBitlengths(b, M)
montyMul(r, a, r2ModN, N, negInvModWord)
let nLen = M.numLimbs()
setZero(r)
func montyResidue*(a: BigIntViewMut, N: BigIntViewConst) =
## Transform a bigint ``a`` from it's natural representation (mod N)
## to a the Montgomery n-residue representation
##
## Modular shift - based
##
## with W = N.numLimbs()
## and R = (2^WordBitSize)^W
##
## Does "a * R (mod N)"
##
## `a`: The source BigInt in the natural representation. `a` in [0, N) range
## `N`: The field modulus. N must be odd.
##
## Important: `a` is overwritten
# Reference: https://eprint.iacr.org/2017/1057.pdf
checkValidModulus(N)
checkOddModulus(N)
checkMatchingBitlengths(a, N)
var r_hi = Zero # represents the high word that is used in intermediate computation before reduction mod M
for i in 0 ..< nLen:
let zi = (r[0] + wordMul(a[i], b[0])).wordMul(negInvModWord)
var carry = Zero
for j in 0 ..< nLen:
let z = DoubleWord(r[j]) + unsafeExtPrecMul(a[i], b[j]) +
unsafeExtPrecMul(zi, M[j]) + DoubleWord(carry)
carry = Word(z shr WordBitSize)
if j != 0:
r[j-1] = Word(z) and MaxWord
r_hi += carry
r[^1] = r_hi and MaxWord
r_hi = r_hi shr WordBitSize
# If the extra word is not zero or if r-M does not borrow (i.e. r > M)
# Then substract M
discard r.sub(M, r_hi.isNonZero() or not r.sub(M, CtFalse))
let nLen = N.numLimbs()
for i in countdown(nLen, 1):
a.shlAddMod(Zero, N)

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@ -23,7 +23,9 @@
import
../primitives/constant_time,
../config/[common, curves],
./bigints_checked, ./precomputed
./bigints_checked,
# TODO: should be a const/proc in curves.nim
./precomputed
# type
# `Fq`*[C: static Curve] = object
@ -51,8 +53,7 @@ debug:
func fromBig*(T: type Fq, src: BigInt): T =
## Convert a BigInt to its Montgomery form
result.mres = src
result.mres.unsafeMontyResidue(Fq.C.Mod)
result.mres.unsafeMontyResidue(src, Fq.C.Mod.mres, r2mod(Fq.C.Mod.mres), neginvModWord(Fq.C.Mod.mres))
func toBig*(src: Fq): auto =
## Convert a finite-field element to a BigInt in natral representation

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@ -14,19 +14,73 @@ import
# Precomputed constants
# ############################################################
# ############################################################
#
# Modular primitives
#
# ############################################################
#
# Those primitives are intended to be compile-time only
# They are generic over the bitsize: enabling them at runtime
# would create a copy for each bitsize used (monomorphization)
# leading to code-bloat.
func double(a: var BigInt): CTBool[Word] =
## In-place multiprecision double
## a -> 2a
for i in 0 ..< a.limbs.len:
BaseType(a.limbs[i]) *= 2
a.limbs[i] += Word(result)
result = a.limbs[i].isMsbSet()
a.limbs[i] = a.limbs[i] and MaxWord
func sub(a: var BigInt, b: BigInt, ctl: CTBool[Word]): CTBool[Word] =
## In-place optional substraction
for i in 0 ..< a.limbs.len:
let new_a = a.limbs[i] - b.limbs[i] - Word(result)
result = new_a.isMsbSet()
a.limbs[i] = ctl.mux(new_a and MaxWord, a.limbs[i])
func doubleMod(a: var BigInt, M: BigInt) =
## In-place modular double
## a -> 2a (mod M)
##
## It is NOT constant-time and is intended
## only for compile-time precomputation
## of non-secret data.
var ctl = double(a)
ctl = ctl or not a.sub(M, CtFalse)
discard a.sub(M, ctl)
# ############################################################
#
# Montgomery Magic Constants precomputation
#
# ############################################################
func checkOddModulus(M: BigInt) =
doAssert bool(BaseType(M.limbs[0]) and 1), "Internal Error: the modulus must be odd to use the Montgomery representation."
import strutils
func checkValidModulus(M: BigInt) =
const expectedMsb = M.bits-1 - WordBitSize * (M.limbs.len - 1)
let msb = log2(BaseType(M.limbs[^1]))
doAssert msb == expectedMsb, "Internal Error: the modulus must use all declared bits and only those"
func negInvModWord*(M: BigInt): BaseType =
## Returns the Montgomery domain magic constant for the input modulus:
##
## µ = -1/M[0] mod M
## µ ≡ -1/M[0] (mod Word)
##
## M[0] is the least significant limb of M
## M must be odd and greater than 2.
##
## Assuming 63-bit words:
##
## µ ≡ -1/M[0] (mod 2^63)
# We use BaseType for return value because static distinct type
# confuses Nim semchecks [UPSTREAM BUG]
# We don't enforce compile-time evaluation here
@ -43,7 +97,7 @@ func negInvModWord*(M: BigInt): BaseType =
# - http://marc-b-reynolds.github.io/math/2017/09/18/ModInverse.html
# For Montgomery magic number, we are in a special case
# where a = M and m = 2^LimbSize.
# where a = M and m = 2^WordBitsize.
# For a and m to be coprimes, a must be odd.
# We have the following relation
@ -56,6 +110,9 @@ func negInvModWord*(M: BigInt): BaseType =
# To get the the modular inverse of 2^k' with arbitrary k' (like k=63 in our case)
# we can do modInv(a, 2^64) mod 2^63 as mentionned in Koc paper.
checkOddModulus(M)
checkValidModulus(M)
let
M0 = BaseType(M.limbs[0])
k = log2(WordPhysBitSize)
@ -66,3 +123,37 @@ func negInvModWord*(M: BigInt): BaseType =
# Our actual word size is 2^63 not 2^64
result = result and BaseType(MaxWord)
func r2mod*(M: BigInt): BigInt =
## Returns the Montgomery domain magic constant for the input modulus:
##
## R² ≡ R² (mod M) with R = (2^WordBitSize)^numWords
##
## Assuming a field modulus of size 256-bit with 63-bit words, we require 5 words
## R² ≡ ((2^63)^5)^2 (mod M) = 2^630 (mod M)
# Algorithm
# Bos and Montgomery, Montgomery Arithmetic from a Software Perspective
# https://eprint.iacr.org/2017/1057.pdf
#
# For R = r^n = 2^wn and 2^(wn 1) ≤ N < 2^wn
# r^n = 2^63 in on 64-bit and w the number of words
#
# 1. C0 = 2^(wn - 1), the power of two immediately less than N
# 2. for i in 1 ... wn+1
# Ci = C(i-1) + C(i-1) (mod M)
#
# Thus: C(wn+1) ≡ 2^(wn+1) C0 ≡ 2^(wn + 1) 2^(wn - 1) ≡ 2^(2wn) ≡ (2^wn)^2 ≡ R² (mod M)
checkOddModulus(M)
checkValidModulus(M)
result.setInternalBitLength()
const
w = M.limbs.len
msb = M.bits-1 - WordBitSize * (w - 1)
result.limbs[^1] = Word(1 shl msb) # C0 = 2^(wn-1), the power of 2 immediatly less than the modulus
for _ in (w-1)*WordBitSize + msb ..< w * WordBitSize * 2:
result.doubleMod(M)

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@ -151,7 +151,7 @@ template isMsbSet*[T: Ct](x: T): CTBool[T] =
const msb_pos = T.sizeof * 8 - 1
(CTBool[T])(x shr msb_pos)
func log2*(x: uint32): uint32 {.compileTime.} =
func log2*(x: uint32): uint32 =
## Find the log base 2 of a 32-bit or less integer.
## using De Bruijn multiplication
## Works at compile-time, guaranteed constant-time.